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Find three consecutive integers whose sum is -42.
A-12, -14, and -16
B-13, -15, and -17
C-14, -14, and -14
D-13, -14, and -15
Answer & Solution
Correct answer: D. -13, -14, and -15
1. Let n equal the first integer, so the next two consecutive integers are n plus 1 and n plus 2.
2. The sum translates to n plus (n plus 1) plus (n plus 2) equals negative 42.
3. Combine like terms: 3n plus 3 equals negative 42.
4. Subtract 3 and divide by 3 to get n equals negative 15, so the three integers are -15, -14, and -13.
5. Check: -13 plus (-14) plus (-15) equals -42.
_Source: OpenStax Elementary Algebra (CC BY 4.0), Ch 3 "Math Models", section 3.1 Use a Problem-Solving Strategy_
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