Factor: 81y^2 - 72y + 16.
A(9y-4)(9y-4)
B(9y+4)(9y+4)
C(9y-8)(9y-2)
D(81y-4)(y-4)
Answer & Solution
Correct answer: A. (9y-4)(9y-4)
1. Check that the first and last terms are perfect squares: 81y squared is (9y) squared, and 16 is 4 squared.
2. The middle term is negative, so the pattern to use is a squared - 2ab + b squared, which factors to (a - b) squared.
3. Check the middle term: twice the product of 9y and 4 is 72y, which matches the size of the middle term.
4. Write the square of the binomial: (9y - 4)(9y - 4), and check by multiplying: 81y squared - 36y - 36y + 16 gives back 81y squared - 72y + 16.
_Source: OpenStax Elementary Algebra (CC BY 4.0), Ch 7 "Factoring", section 7.4 Factor Special Products_
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