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What is the completely factored form of 4y^2 + 24y + 28?
A4(y^2+6y+7)
B4(y^2+24y+7)
C4(y^2-6y+7)
Dy(4y+24+28)
Answer & Solution
Correct answer: A. 4(y^2+6y+7)
1. Find the GCF of 4y squared, 24y, and 28, which is 4.
2. Rewrite each term as a product using the GCF: 4y squared is 4 times y squared, 24y is 4 times 6y, and 28 is 4 times 7.
3. Factor to get 4(y squared + 6y + 7).
4. Check by multiplying: 4 times y squared, plus 4 times 6y, plus 4 times 7, gives back 4y squared + 24y + 28.
_Source: OpenStax Elementary Algebra (CC BY 4.0), Ch 7 "Factoring", section 7.1 Greatest Common Factor and Factor by Grouping_
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