alleryA 5 kg object slides on a rough surface and experiences a friction force of 8 N. Its DECELERATION is:
A8 m/s²
B1.6 m/s²
C2 m/s²
D40 m/s²
Answer & Solution
Correct answer: B. 1.6 m/s²
**Newton's second law:** F = ma → a = F/m = 8 N / 5 kg = 1.6 m/s².
The friction force decelerates the object (acts opposite to motion).
**So the object slows by 1.6 m/s every second until it stops.**
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