alleryStart learning →If 120 J of heat is transferred into a system at a constant temperature of 350 K, what is the change in entropy?
A0.343 J/K
B2.92 J/K
C34.3 J/K
D42,000 J/K
Answer & Solution
Correct answer: A. 0.343 J/K
1. Change in entropy is ΔS = Q divided by T.
2. Substitute Q = 120 J and T = 350 K.
3. Dividing gives ΔS = 0.343 J/K.
4. 2.92 J/K inverts the division, and 42,000 J/K multiplies the two values instead of dividing.
5. 34.3 J/K shifts the decimal point by one place from the correct value.
6. So 0.343 J/K is correct.
_Source: OpenStax Physics (CC BY 4.0), Ch 12 "Thermodynamics", section 12.3 Second Law of Thermodynamics: Entropy_
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