A woman backs her car out of her garage with an acceleration of 1.40 m/s^2. How long does it take her to reach a speed of 2.00 m/s?
A0.70 s
B1.43 s
C2.80 s
D3.40 s
Answer & Solution
Correct answer: B. 1.43 s
1. Starting from rest, the needed velocity change is 2.00 m/s.
2. Rearrange a = delta v / delta t to get delta t = delta v / a.
3. delta t = 2.00 m/s / 1.40 m/s^2 = 1.43 s.
_Source: OpenStax Physics (CC BY 4.0), Ch 3 "Acceleration", section 3.1 Acceleration_
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