alleryStart learning →A cheetah accelerates from rest to a speed of 30.0 m/s in 7.00 s. What is its acceleration?
A0.23 m/s^2
B4.29 m/s^2
C7.00 m/s^2
D30.0 m/s^2
Answer & Solution
Correct answer: B. 4.29 m/s^2
1. Starting from rest, delta v equals the final speed, 30.0 m/s.
2. a = delta v / delta t = 30.0 m/s / 7.00 s.
3. a = 4.29 m/s^2.
_Source: OpenStax Physics (CC BY 4.0), Ch 3 "Acceleration", section 3.1 Acceleration_
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