A subway train accelerates from rest to 30.0 km/h (8.333 m/s) in 20.0 s. What is its average acceleration?
A0.417 m/s^2
B1.50 m/s^2
C8.33 m/s^2
D166 m/s^2
Answer & Solution
Correct answer: A. 0.417 m/s^2
1. Starting from rest means v_0 = 0, and the final speed converts to 8.333 m/s.
2. delta v = 8.333 m/s - 0 = 8.333 m/s.
3. a = delta v / delta t = 8.333 m/s / 20.0 s = 0.417 m/s^2.
_Source: OpenStax Physics (CC BY 4.0), Ch 3 "Acceleration", section 3.1 Acceleration_
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