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Rhianna walks with average velocity v_avg for half of the time that Logan walks, starting from the same point and going the same direction. If Logan covers three times the distance Rhianna covers, what is Logan's average velocity in terms of Rhianna's?
A(2/3) v_avg
B(1) v_avg
C(3/2) v_avg
D(3) v_avg
Answer & Solution
Correct answer: C. (3/2) v_avg
1. Let Rhianna's time be t, so her distance is v_avg x t, and Logan's time is 2t.
2. Logan's distance is three times Rhianna's: 3 x (v_avg x t).
3. Logan's velocity = distance / time = (3 v_avg t) / (2t) = (3/2) v_avg.
_Source: OpenStax Physics (CC BY 4.0), Ch 2 "Motion in One Dimension", section 2.2 Speed and Velocity_
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