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A father walks in a straight line to a bus stop 75 m away at 2.2 m/s, while his daughter runs a varied path at 3.5 m/s and arrives at the same moment. How long does the trip take?
A21 s
B34 s
C75 s
D119 s
Answer & Solution
Correct answer: B. 34 s
1. The father walks straight to the stop, so his distance equals his displacement of 75 m.
2. time = distance / speed = 75 m / 2.2 m/s = 34.1 s.
3. Rounded to two significant figures, the trip takes 34 s.
_Source: OpenStax Physics (CC BY 4.0), Ch 2 "Motion in One Dimension", section 2.2 Speed and Velocity_
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