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On an axis where moving from right to left counts as the positive direction, a student walks 32 m to the right and then 17 m to the left. What are the student's displacement and total distance?
ADisplacement 49 m, distance 15 m
BDisplacement 15 m, distance 49 m
CDisplacement -15 m, distance 49 m
DDisplacement -49 m, distance 15 m
Answer & Solution
Correct answer: C. Displacement -15 m, distance 49 m
1. Right to left is positive here, so moving right is the negative direction and moving left is positive.
2. Walking 32 m right is -32 m, and walking 17 m left is +17 m.
3. Displacement = -32 m + 17 m = -15 m.
4. Distance simply adds the path lengths regardless of sign: 32 m + 17 m = 49 m.
5. Choosing the wrong sign convention here, by treating rightward as positive, is the trap that produces +15 m instead.
_Source: OpenStax Physics (CC BY 4.0), Ch 2 "Motion in One Dimension", section 2.1 Relative Motion, Distance, and Displacement_
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