A photon has a wavelength of 500 nm. Using p equals h over lambda with h equals 6.63 x 10^-34 J s, what is its momentum?

1. Photon momentum is p = h / lambda. 2. Substituting values: p = (6.63 x 10^-34 J s) / (500 x 10^-9 m) = (6.63 x 10^-34) / (5.00 x 10^-7). 3. Carrying out the division gives p = 1.33 x 10^-27 kg m/s. 4. 1.33 x 10^-24 kg m/s misplaces the wavelength's exponent by three powers of ten. 5. 3.32 x 10^-41 kg m/s comes from multiplying h and lambda instead of dividing one by the other. _Source: OpenStax Physics (CC BY 4.0), Ch 21 "The Quantum Nature of Light", section 21.3 The Dual Nature of Light_