A car starts from rest and reaches 30 m/s in 6 seconds. The distance covered in this time is:
A30 m
B60 m
C180 m
D90 m
Answer & Solution
Correct answer: D. 90 m
u = 0, v = 30 m/s, t = 6 s.
Acceleration a = (v − u)/t = 30/6 = 5 m/s².
Distance s = ut + ½at² = 0 + ½ × 5 × 36 = 90 m.
(Alternative: average velocity = (0 + 30)/2 = 15 m/s, distance = avg × t = 15 × 6 = 90 m.)
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