A car starts from rest and reaches 30 m/s in 6 seconds. The distance covered in this time is:
A30 m
B60 m
C180 m
D90 m
Answer & Solution
Correct answer: D. 90 m
u = 0, v = 30 m/s, t = 6 s. Acceleration a = (v − u)/t = 30/6 = 5 m/s². Distance s = ut + ½at² = 0 + ½ × 5 × 36 = 90 m. (Alternative: average velocity = (0 + 30)/2 = 15 m/s, distance = avg × t = 15 × 6 = 90 m.)
Related questions
In a velocity-time graph, the AREA UNDER the curve gives:In a distance-time graph, a STRAIGHT HORIZONTAL line means:A car braking uniformly decelerates from 20 m/s to rest with deceleration 5 m/s². The brakA train starts from rest (u = 0) and accelerates uniformly at a = 2 m/s² for t = 10 s. TheA car starting at u = 5 m/s accelerates uniformly at a = 2 m/s² for t = 4 s. Its final velA car accelerates from 10 m/s to 20 m/s in 5 seconds. Its acceleration is:A cab covers 60 km in 1.5 hours. Its AVERAGE SPEED is:A student runs once around a circular school playground of perimeter 400 metres and return