Inflated pods are dominant to constricted. An F2 generation contains 650 inflated-pod plants. About how many constricted-pod plants are expected?

1. A monohybrid F2 for a dominant and recessive pair splits 3 dominant to 1 recessive. 2. So the inflated plants make up 3 parts and the constricted plants make up 1 part. 3. One part equals the inflated count divided by 3, which is 650 divided by 3. 4. That gives about 217 constricted-pod plants. 5. Check the total: 650 plus 217 is 867, and a quarter of 867 is about 217, which agrees. 6. About 600 would be close to a 1 to 1 split, which no dominant and recessive F2 gives. 7. About 468 is close to two thirds of 650, and about 165 is close to a quarter of 650, and neither matches a 3 to 1 split. _Source: OpenStax Biology (1st ed., CC BY 4.0), Ch 12 "Mendel's Experiments and Heredity", review questions_