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In a dihybrid F2 generation, what is the probability of showing the dominant trait for both characteristics?

A1/16
B3/16
C9/16
D1/4
Answer & Solution
Correct answer: C. 9/16
1. Each characteristic on its own gives a 3 to 1 ratio, so the chance of the dominant trait is 3/4. 2. The two characteristics assort independently, and the question asks for one dominant trait and the other, so use the product rule. 3. Multiply: 3/4 times 3/4 equals 9/16. 4. A value of 1/16 is the double recessive class, and 3/16 is one dominant with one recessive. 5. A value of 1/4 would be the answer for a single gene, not for two. _Source: OpenStax Biology (1st ed., CC BY 4.0), Ch 12 "Mendel's Experiments and Heredity", section 12.1 Mendel's Experiments and the Laws of Probability_
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