The same 75.0 kg man now rides the lift upward at a constant speed of 1 m/s. What does the scale read?

1. For any constant velocity the change in velocity is zero, so the acceleration is zero. 2. The scale reading is the mass times the acceleration plus the mass times the acceleration due to gravity. 3. With zero acceleration the first term vanishes. 4. Substitute the values: (75.0 kg)(9.80 m/s^2) = 735 N. 5. That equals his weight, and it holds whether the lift moves up, moves down, or stands still. _Source: OpenStax College Physics (CC BY 4.0), Ch 4 "Dynamics: Force and Newton's Laws of Motion", section 4.7 Further Applications of Newton's Laws of Motion_