A jogger runs along a straight road with an average velocity of 4.00 m/s for 2.00 min, starting from a position of zero. What is his final position?

1. Identify the knowns: the average velocity is 4.00 m/s, the time is 2.00 min and the initial position is 0 m. 2. Convert the time to SI units: 2.00 min x 60 s per min = 120 s. 3. Final position equals initial position plus average velocity times time. 4. Substitute the values: 0 + (4.00 m/s)(120 s) = 480 m. 5. Using 2.00 s instead of 120 s gives 8.00 m, which is the unit trap. _Source: OpenStax College Physics (CC BY 4.0), Ch 2 "Kinematics", section 2.5 Motion Equations for Constant Acceleration in One Dimension_