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The graph of $y=x^2-3x-4$ is shown in the figure. What are the zeroes of the polynomial $x^2-3x-4$? 
A$-1$ and $4$
B$1$ and $4$
C$-4$ and $1$
D$0$ and $4$
Answer & Solution
Correct answer: A. $-1$ and $4$
The zeroes of a polynomial are the $x$-coordinates where its graph cuts the $x$-axis. In the figure, the parabola intersects the $x$-axis at $(-1,0)$ and $(4,0)$. Hence the zeroes are $-1$ and $4$.
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