Home › UP Board Class 10 › Mathematics › The graph of $y=x^2-3x-4$ is shown in the figure…
The graph of $y=x^2-3x-4$ is shown in the figure. What are the zeroes of the polynomial $x^2-3x-4$? 
A$-1$ and $4$
B$1$ and $4$
C$-4$ and $1$
D$0$ and $4$
Answer & Solution
Correct answer: A. $-1$ and $4$
The zeroes of a polynomial are the $x$-coordinates where its graph cuts the $x$-axis. In the figure, the parabola intersects the $x$-axis at $(-1,0)$ and $(4,0)$. Hence the zeroes are $-1$ and $4$.
Related questions
What is the derivative of $x^x$ for $x>0$?If $y=x^{\tan^{-1}x}$, then $\dfrac{dy}{dx}$ equalsThe derivative of $ in^{-1}x$ isThe derivative of $\cos^{-1}x$ isWhat is $\dfrac{d}{dx}(\tan^{-1}x)$?If $y=\dfrac{1}{x^n}$, then $\dfrac{dy}{dx}$ isWhich identity is correct?For the expression $ qrt{1-x^2}$, a useful trigonometric substitution is