Drawing two marbles without replacement from three red and eight blue, what is the probability that both are blue?

1. The first draw gives blue with probability 8/11. 2. That marble is not replaced, so seven blue marbles remain among ten. 3. The second draw gives blue with probability 7/10, and multiplying gives 56/110. 4. The value 64/121 assumes replacement, which would leave all eight blue marbles in the urn. _Source: OpenStax Introductory Business Statistics (CC BY 4.0), Ch 3 "Probability Topics", section 3.4 Contingency Tables and Probability Trees_