An urn holds three red and eight blue balls, and two are drawn with replacement. What is the probability that both are red?

1. With replacement the first ball goes back, so both draws face the same 11 balls. 2. Each draw gives red with probability 3/11. 3. Multiplying gives 3/11 times 3/11, which is 9/121. 4. The value 6/110 is the answer without replacement, where the second draw faces only ten balls. _Source: OpenStax Introductory Business Statistics (CC BY 4.0), Ch 3 "Probability Topics", section 3.4 Contingency Tables and Probability Trees_