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Of 800 athletes, 514 had no injury last year and 295 of those stretch before exercising. What is the probability of stretching given no injury?
AIt is 350/800
BIt is 295/350
CIt is 514/800
DIt is 295/514
Answer & Solution
Correct answer: D. It is 295/514
1. Conditioning on no injury reduces the sample space to the 514 uninjured athletes.
2. Of those, 295 stretch before exercising.
3. The conditional probability is therefore 295/514.
4. Using 350 as the denominator conditions on stretching instead and answers the reverse question.
_Source: OpenStax Introductory Business Statistics (CC BY 4.0), Ch 3 "Probability Topics", section 3.4 Contingency Tables and Probability Trees_
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