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In a box of cookies 36 percent contain chocolate, 12 percent contain nuts and eight percent contain both. What share contain chocolate or nuts?
AIt is 0.48 of the cookies
BIt is 0.56 of the cookies
CIt is 0.40 of the cookies
DIt is 0.60 of the cookies
Answer & Solution
Correct answer: C. It is 0.40 of the cookies
1. The addition rule gives 0.36 plus 0.12 minus 0.08.
2. The two parts add to 0.48.
3. Subtracting the overlap of 0.08 leaves 0.40 of the cookies.
4. Stopping at 0.48 counts the cookies with both chocolate and nuts twice over.
_Source: OpenStax Introductory Business Statistics (CC BY 4.0), Ch 3 "Probability Topics", section 3.3 Two Basic Rules of Probability_
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