Carlos scores on his first attempt with probability 0.65, and scores on the second given the first with probability 0.90. What is the probability he scores both?

1. The multiplication rule gives P(both) as P(first) times P(second given first). 2. That is 0.65 multiplied by 0.90. 3. The product is 0.585, so he scores both goals with probability 0.585. 4. The value 0.423 comes from multiplying 0.65 by 0.65, which would assume the two attempts are independent. _Source: OpenStax Introductory Business Statistics (CC BY 4.0), Ch 3 "Probability Topics", section 3.3 Two Basic Rules of Probability_