Flip a coin then roll a die. A is heads with an even face and B is heads with a three, so P(A) is 3/12 and P(B) is 1/12. How do A and B relate?

1. The combined experiment has 2 times 6, which is 12 equally likely outcomes. 2. Event A holds H2, H4 and H6 and event B holds H3 alone. 3. No outcome belongs to both, so the joint probability is zero and the events are mutually exclusive. 4. The product of the two probabilities is 3/12 times 1/12, which is 3/144 and is not zero. 5. Since the joint probability of zero does not match that product, the events are dependent. 6. This is the standard trap: mutually exclusive events with non-zero probabilities are always dependent, because one occurring forces the other to fail. _Source: OpenStax Introductory Business Statistics (CC BY 4.0), Ch 3 "Probability Topics", section 3.2 Independent and Mutually Exclusive Events_