In the same box, G is a card numbered above three and H is a blue card numbered one to four. P(G) is 2/8 and P(G given H) is 1/4. What follows?

1. The plain probability of G is 2/8, which simplifies to 1/4. 2. The conditional probability of G given H is also 1/4. 3. Knowing that H occurred therefore leaves the chance of G unchanged. 4. That satisfies one of the three independence conditions, which is all that is required. 5. The two events are not mutually exclusive, since the blue card numbered four belongs to both. 6. Dependence would require the conditional to differ from the plain probability, which it does not. _Source: OpenStax Introductory Business Statistics (CC BY 4.0), Ch 3 "Probability Topics", section 3.2 Independent and Mutually Exclusive Events_