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AI divided by omega, in kg m^2 s
BI times omega, in units of kg m/s
CI times omega, in units of kg m^2/s
DI times omega squared, in kg m^2/s
Answer & Solution
Correct answer: C. I times omega, in units of kg m^2/s
1. Linear momentum is p = m v, so the rotational analogue replaces m by I and v by omega.
2. That gives L = I omega, the product of moment of inertia and angular velocity.
3. Moment of inertia is in kg m^2 and angular velocity in rad/s, and radians are dimensionless.
4. So the units are kg m^2/s, distinct from the kg m/s of linear momentum.
5. Squaring omega would give something with the units of energy times seconds, not momentum.
_Source: OpenStax College Physics (CC BY 4.0), Ch 10 "Rotational Motion and Angular Momentum", section 10.5 Angular Momentum and Its Conservation_
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