A bicycle wheel is spun from rest up to 250 rpm in 5.00 s. What is its angular acceleration?
A50.0 rad/s^2
B26.2 rad/s^2
C5.24 rad/s^2
D1.31 rad/s^2
Answer & Solution
Correct answer: C. 5.24 rad/s^2
1. Convert the final angular velocity first, since alpha must come out in rad/s^2.
2. omega = 250 rev/min times 2 pi rad/rev times 1 min / 60 s = 26.2 rad/s.
3. Starting from rest, delta omega = 26.2 rad/s over delta t = 5.00 s.
4. So alpha = 26.2 rad/s / 5.00 s = 5.24 rad/s^2.
5. Using 250 rpm directly without converting gives 50.0 rad/s^2, which mixes units.
_Source: OpenStax College Physics (CC BY 4.0), Ch 10 "Rotational Motion and Angular Momentum", section 10.1 Angular Acceleration_
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