What volume of 0.575 M glucose can be prepared from 50.00 mL of 3.00 M glucose?

1. The stock volume and concentration are known along with the target concentration, so V2 is the unknown. 2. Rearrange the dilution equation to V2 = C1V1 / C2. 3. Convert the stock volume: 50.00 mL = 0.05000 L. 4. Substituting gives V2 = 3.00 M x 0.05000 L / 0.575 M. 5. The numerator is 0.150 mol of glucose. 6. Dividing by 0.575 M gives 0.261 L of diluted solution. 7. The value 0.150 L is the numerator alone, and 0.00958 L multiplies by 0.575 M instead of dividing. _Source: OpenStax Chemistry (CC BY 4.0), Ch 3 "Composition of Substances and Solutions", section 3.3 Molarity_