What volume of 1.59 M KOH is needed to prepare 5.00 L of 0.100 M KOH?

1. Here the stock concentration and both properties of the diluted solution are known, so V1 is the unknown. 2. Rearrange the dilution equation to V1 = C2V2 / C1. 3. Substituting gives V1 = 0.100 M x 5.00 L / 1.59 M. 4. The numerator is 0.500 mol of KOH. 5. Dividing by 1.59 M gives 0.314 L of the stock solution. 6. The diluted concentration is about one sixteenth of the stock, so the stock volume should be about one sixteenth of 5.00 L. 7. The value 0.795 L multiplies by 1.59 M instead of dividing, and 0.500 L stops at the numerator. _Source: OpenStax Chemistry (CC BY 4.0), Ch 3 "Composition of Substances and Solutions", section 3.3 Molarity_