If 0.850 L of 5.00 M copper nitrate is diluted with water to 1.80 L, what is the new molarity?

1. Use the dilution equation C1V1 = C2V2 and rearrange for C2. 2. That gives C2 = C1V1 / V2. 3. Substituting gives C2 = 5.00 mol/L x 0.850 L / 1.80 L. 4. The numerator is 4.25 mol and dividing by 1.80 L gives 2.36 M. 5. The volume more than doubles, so the answer should be a bit under half of 5 M, which it is. 6. The value 4.25 M is the mole count from the numerator, reported without the final division. _Source: OpenStax Chemistry (CC BY 4.0), Ch 3 "Composition of Substances and Solutions", section 3.3 Molarity_