What volume of 0.839 M vinegar contains 75.6 g of acetic acid, molar mass 60.05 g/mol?

1. First convert the mass of solute into an amount using the molar mass. 2. That gives 75.6 g / 60.05 g/mol = 1.2590 mol of acetic acid. 3. Then use the molarity to convert the amount into a volume of solution. 4. That gives 1.2590 mol / 0.839 mol per litre. 5. The volume is 1.50 L of solution. 6. Combining both conversions into a single step avoids rounding the intermediate mole count. 7. The value 1.06 L multiplies by the molarity instead of dividing by it. 8. The value 3.81 L divides by the molarity twice over, once at each stage. _Source: OpenStax Chemistry (CC BY 4.0), Ch 3 "Composition of Substances and Solutions", section 3.3 Molarity_