How many moles of NaCl are contained in 0.250 L of a 5.30 M solution?

1. Rearranging the definition of molarity gives moles of solute = molarity x volume in litres. 2. Substituting gives 5.30 mol/L x 0.250 L. 3. The product is 1.325 mol of NaCl. 4. Units cancel correctly, since mol/L multiplied by L leaves mol. 5. The value 21.2 mol comes from dividing by 0.250 L instead of multiplying by it. _Source: OpenStax Chemistry (CC BY 4.0), Ch 3 "Composition of Substances and Solutions", section 3.3 Molarity_