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How many hydrogen atoms are in 9.213 g of C4H10, which contains 9.545 x 10^22 molecules?

A3.82 x 10^23 atoms
B9.545 x 10^22 atoms
C5.73 x 10^23 atoms
D9.545 x 10^23 atoms
Answer & Solution
Correct answer: D. 9.545 x 10^23 atoms
1. The formula C4H10 shows ten hydrogen atoms in each molecule. 2. The sample holds 9.545 x 10^22 molecules. 3. Multiply the two: 9.545 x 10^22 molecules x 10 hydrogen atoms per molecule. 4. The product is 9.545 x 10^23 hydrogen atoms. 5. Multiplying by ten raises the exponent by one and leaves the digits unchanged. 6. The value 3.82 x 10^23 uses the four carbon atoms rather than the ten hydrogen atoms. 7. Repeating 9.545 x 10^22 counts molecules, not the atoms inside them. _Source: OpenStax Chemistry (CC BY 4.0), Ch 3 "Composition of Substances and Solutions", section 3.1 Formula Mass and the Mole Concept_
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