Chloroform is CHCl3. Using C = 12.01 amu, H = 1.008 amu and Cl = 35.45 amu, what is its molecular mass?

1. One chloroform molecule holds one carbon atom, one hydrogen atom and three chlorine atoms. 2. Carbon contributes 1 x 12.01 amu = 12.01 amu. 3. Hydrogen contributes 1 x 1.008 amu = 1.008 amu. 4. Chlorine contributes 3 x 35.45 amu = 106.35 amu. 5. Adding gives 12.01 + 1.008 + 106.35 = 119.37 amu. 6. The value 48.47 amu comes from counting only one chlorine atom instead of three. _Source: OpenStax Chemistry (CC BY 4.0), Ch 3 "Composition of Substances and Solutions", section 3.1 Formula Mass and the Mole Concept_