Complete the half-life rules
Exercise and reference answers
- Missing parts
- Answer
- 0.693/k
- Choices
- 1/k
- k/0.693
- 0.693/k
- Answer
- 5.02
- Choices
- 7.25
- 5.02
- 1.38
- Answer
- 1/(k[A]0)
- Choices
- 1/(k[A]0)
- 0.693/k
- 2k/[A]0
- Complete the statement
- A first order half-life is {0}, so a decay with k = 0.138 per day halves in about {1} days. A second order half-life instead reads {2}.
- Instructions
- Tap the right entry for each blank.
Explanation
_Source: OpenStax Chemistry, section 12.4 Integrated Rate Laws_