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Complete the half-life rules

Exercise and reference answers

Missing parts
  1. Answer
    0.693/k
    Choices
    1. 1/k
    2. k/0.693
    3. 0.693/k
  2. Answer
    5.02
    Choices
    1. 7.25
    2. 5.02
    3. 1.38
  3. Answer
    1/(k[A]0)
    Choices
    1. 1/(k[A]0)
    2. 0.693/k
    3. 2k/[A]0
Complete the statement
A first order half-life is {0}, so a decay with k = 0.138 per day halves in about {1} days. A second order half-life instead reads {2}.
Instructions
Tap the right entry for each blank.

Explanation

_Source: OpenStax Chemistry, section 12.4 Integrated Rate Laws_
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