Find the sum of the infinite geometric series whose first term is 4,374 and whose common ratio is -1/3.
AS = 6,561.0
BS = 2,916.0
CS = 2,187.0
DS = 3,280.5
Answer & Solution
Correct answer: D. S = 3,280.5
1. First check the sum exists: the ratio -1/3 lies strictly between -1 and 1, so it does.
2. The infinite sum formula is S = a_1/(1 - r).
3. The denominator is 1 - (-1/3) = 1 + 1/3 = 4/3.
4. So S = 4,374 divided by 4/3.
5. Dividing by 4/3 is the same as multiplying by 3/4, giving 4,374 times 3/4.
6. That is 13,122/4 = 3,280.5.
7. Dropping the sign and using 1 - 1/3 = 2/3 in the denominator would give 6,561, which is the commonest error with a negative ratio.
_Source: OpenStax Algebra and Trigonometry (CC BY 4.0), Ch 13 "Sequences, Probability and Counting Theory", section 13.4 Series and Their Notations_
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