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Which of the following best states the theoretical probability of an event $E$ when all outcomes are equally likely?

A$P(E)=\dfrac{\text{number of trials}}{\text{number of favourable outcomes}}$
B$P(E)=\dfrac{\text{number of favourable outcomes to }E}{\text{number of all possible outcomes}}$
C$P(E)=\dfrac{\text{number of unfavourable outcomes}}{\text{number of all possible outcomes}}$
D$P(E)=\dfrac{\text{number of possible outcomes}}{\text{number of favourable outcomes to }E}$
Answer & Solution
Correct answer: B. $P(E)=\dfrac{\text{number of favourable outcomes to }E}{\text{number of all possible outcomes}}$
For equally likely outcomes, theoretical probability is defined as the ratio of favourable outcomes to total possible outcomes. Hence option B is correct.
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