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When three resistors are connected in series, the equivalent resistance is
A$\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}$
Bless than the smallest resistance
Cequal to each resistor's value
D$R_1 + R_2 + R_3$
Answer & Solution
Correct answer: D. $R_1 + R_2 + R_3$
1. In series the same current flows and the voltages add.
2. The equivalent resistance is the **sum**: $R_s = R_1 + R_2 + R_3$.
3. So the series total is always larger than any single resistor.
_Source: Karnataka SSLC (KSEEB) Class 10 Science, Ch12 'Electricity', §12.5 (series)_
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