Home › JEE Advanced › Physics › Rotational Motion › The **angular momentum** of a particle of moment…
The **angular momentum** of a particle of momentum $\vec p$ at position $\vec r$ (from origin) is:
A$\vec p \cdot \vec r$
B$\vec r \times \vec p$
C$\vec p \times \vec r$
D$|\vec r||\vec p|$ always
Answer & Solution
Correct answer: B. $\vec r \times \vec p$
$\vec L = \vec r \times \vec p$ (right-hand rule). Note $\vec r \times \vec p = -\vec p \times \vec r$, order matters.
Related questions
The branch describing the motion of a rotating rigid body about a fixed axis is rotationalSix washers on a light rod illustrate the moment of inertia of a system of:The more massive an object is, the more of this it has in linear motion:Unlike linear position measured in metres, angular position is measured in units that are:Acceleration caused by the change in direction of tangential velocity is called:Several torques acting about one axis are combined by finding their:The perpendicular distance from the axis to the line of the force is called the:The SI unit of torque is the newton multiplied by the: