alleryThe **angular momentum** of a particle of momentum $\vec p$ at position $\vec r$ (from origin) is:
A$\vec p \cdot \vec r$
B$\vec r \times \vec p$
C$\vec p \times \vec r$
D$|\vec r||\vec p|$ always
Answer & Solution
Correct answer: B. $\vec r \times \vec p$
$\vec L = \vec r \times \vec p$ (right-hand rule).
Note $\vec r \times \vec p = -\vec p \times \vec r$, order matters.
Keep practising System of Particles and Rotational Motion
Browse all System of Particles and Rotational Motion questions for JEE Advanced, or explore more Physics topics.