The polarising angle (Brewster angle) for glass of refractive index 1.5 is
A{'text': 'tan⁻¹(1.5)', 'label': 'A'}
B{'text': 'tan⁻¹(0.667)', 'label': 'B'}
C{'text': 'sin⁻¹(1.5)', 'label': 'C'}
D{'text': 'cos⁻¹(0.667)', 'label': 'D'}
Answer & Solution
Correct answer: A. {'text': 'tan⁻¹(1.5)', 'label': 'A'}
1. Brewster's law: tan(i_B) = n_2/n_1.
2. For glass in air with n = 1.5, tan(i_B) = 1.5.
3. So i_B = tan⁻¹(1.5) ≈ 56.3°.
4. At this angle the reflected light is completely polarised perpendicular to the plane of incidence.
_Source: NCERT Class 12 Physics, Ch 10 "Wave Optics", §10.7_
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