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The polarising angle (Brewster angle) for glass of refractive index 1.5 is

Atan⁻¹(1.5)
Btan⁻¹(0.667)
Csin⁻¹(1.5)
Dcos⁻¹(0.667)
Answer & Solution
Correct answer: A. tan⁻¹(1.5)
1. Brewster's law: tan(i_B) = n_2/n_1. 2. For glass in air with n = 1.5, tan(i_B) = 1.5. 3. So i_B = tan⁻¹(1.5) ≈ 56.3°. 4. At this angle the reflected light is completely polarised perpendicular to the plane of incidence. _Source: syllabus Physics, Ch 10 "Wave Optics", §10.7_
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