The polarising angle (Brewster angle) for glass of refractive index 1.…

Question

The polarising angle (Brewster angle) for glass of refractive index 1.5 is

Accepted Answer

A. {'text': 'tan⁻¹(1.5)', 'label': 'A'}

1. Brewster's law: tan(i_B) = n_2/n_1.
2. For glass in air with n = 1.5, tan(i_B) = 1.5.
3. So i_B = tan⁻¹(1.5) ≈ 56.3°.
4. At this angle the reflected light is completely polarised perpendicular to the plane of incidence.
_Source: NCERT Class 12 Physics, Ch 10 "Wave Optics", §10.7_

Answer

{'text': 'tan⁻¹(0.667)', 'label': 'B'}

Answer

{'text': 'sin⁻¹(1.5)', 'label': 'C'}

Answer

{'text': 'cos⁻¹(0.667)', 'label': 'D'}