For diffraction at a single slit of width a, the angular position of the first minimum is given by
A{'text': 'a cos θ = λ', 'label': 'A'}
B{'text': 'a sin θ = λ/2', 'label': 'B'}
C{'text': 'a sin θ = λ', 'label': 'C'}
D{'text': 'a tan θ = 2λ', 'label': 'D'}
Answer & Solution
Correct answer: C. {'text': 'a sin θ = λ', 'label': 'C'}
1. Single-slit diffraction gives dark fringes at a sin θ = n λ, n = ±1, ±2, …
2. The first minimum (n = 1) is at a sin θ = λ.
3. Note: bright fringes are between minima; the central bright is broader.
4. Half-angular width of central maximum is θ ≈ λ/a for small angles.
_Source: NCERT Class 12 Physics, Ch 10 "Wave Optics", §10.6_
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