For diffraction at a single slit of width a, the angular position of the first minimum is given by
Aa cos θ = λ
Ba sin θ = λ/2
Ca sin θ = λ
Da tan θ = 2λ
Answer & Solution
Correct answer: C. a sin θ = λ
1. Single-slit diffraction gives dark fringes at a sin θ = n λ, n = ±1, ±2, …
2. The first minimum (n = 1) is at a sin θ = λ.
3. Note: bright fringes are between minima; the central bright is broader.
4. Half-angular width of central maximum is θ ≈ λ/a for small angles.
_Source: syllabus Physics, Ch 10 "Wave Optics", §10.6_
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