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The frequency of beats when two waves of frequencies 512 Hz and 508 Hz superpose is

A4 Hz
B1020 Hz
C510 Hz
D0 Hz
Answer & Solution
Correct answer: A. 4 Hz
1. Beats occur when two waves of nearly equal frequencies superpose. 2. The beat frequency is the absolute difference of the two frequencies. 3. |512 − 508| = 4 Hz. 4. So four beats per second are heard. _Source: syllabus Physics, Ch 14 "Waves", §14.7_
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