The frequency of beats when two waves of frequencies 512 Hz and 508 Hz superpose is
A{'text': '4 Hz', 'label': 'A'}
B{'text': '1020 Hz', 'label': 'B'}
C{'text': '510 Hz', 'label': 'C'}
D{'text': '0 Hz', 'label': 'D'}
Answer & Solution
Correct answer: A. {'text': '4 Hz', 'label': 'A'}
1. Beats occur when two waves of nearly equal frequencies superpose.
2. The beat frequency is the absolute difference of the two frequencies.
3. |512 − 508| = 4 Hz.
4. So four beats per second are heard.
_Source: NCERT Class 11 Physics, Ch 14 "Waves", §14.7_
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