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E and F are independent events with P(E) = 0.3 and P(F) = 0.5. Then P(E ∪ F) equals
A{'text': '0.15', 'label': 'A'}
B{'text': '0.85', 'label': 'B'}
C{'text': '0.80', 'label': 'C'}
D{'text': '0.65', 'label': 'D'}
Answer & Solution
Correct answer: D. {'text': '0.65', 'label': 'D'}
1. Addition rule: P(E ∪ F) = P(E) + P(F) − P(E ∩ F).
2. For independent events, P(E ∩ F) = P(E) × P(F) = 0.3 × 0.5 = 0.15.
3. So P(E ∪ F) = 0.3 + 0.5 − 0.15.
4. = 0.65.
_Source: NCERT Class 12 Mathematics, Ch 13 "Probability", §13.4_
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