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A die is rolled and a coin is tossed simultaneously. If E = "die shows an even number" and F = "coin shows head", then P(E ∩ F) is

A{'text': '1/4', 'label': 'A'}
B{'text': '1/6', 'label': 'B'}
C{'text': '1/12', 'label': 'C'}
D{'text': '1/2', 'label': 'D'}
Answer & Solution
Correct answer: A. {'text': '1/4', 'label': 'A'}
1. Die and coin are independent random experiments. 2. P(E) = 3/6 = 1/2 (die shows 2, 4 or 6). 3. P(F) = 1/2 (coin shows head). 4. P(E ∩ F) = P(E) × P(F) = 1/2 × 1/2 = 1/4. _Source: NCERT Class 12 Mathematics, Ch 13 "Probability", §13.4_
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