Home › NEET UG › Chemistry › Electrochemical Series › For an electrochemical cell operating spontaneou…
For an electrochemical cell operating spontaneously, ΔG° is related to E°_cell by
A{'text': 'ΔG° = +nFE°_cell', 'label': 'A'}
B{'text': 'ΔG° = nF / E°_cell', 'label': 'B'}
C{'text': 'ΔG° = −nFE°_cell', 'label': 'C'}
D{'text': 'ΔG° = E°_cell / (nF)', 'label': 'D'}
Answer & Solution
Correct answer: C. {'text': 'ΔG° = −nFE°_cell', 'label': 'C'}
1. Standard cell thermodynamics: ΔG° = −nFE°_cell.
2. Positive E°_cell → negative ΔG° → spontaneous.
3. n is moles of electrons transferred; F is Faraday constant.
4. At non-standard conditions, ΔG = ΔG° + RT ln Q or equivalently ΔG = −nFE_cell.
_Source: NCERT Class 12 Chemistry, Unit 3 "Electrochemistry", §3.3_
Related questions
The electrolytes of the two half-cells are joined by a:The two portions of a galvanic cell are also called:In the Daniell cell, zinc dissolves at the anode and copper:A negative standard potential marks a reducing agent that is:Going from top to bottom of the table, the electrode potential:The weakest oxidising agent in the table of potentials is:The most powerful reducing agent in aqueous solution is:The weakest reducing agent in the table of potentials is: