The specific conductivity of a 0.1 M KCl solution is 1.29 × 10⁻² S/cm.…

Question

The specific conductivity of a 0.1 M KCl solution is 1.29 × 10⁻² S/cm. The molar conductivity is

Accepted Answer

A. {'text': '129 S cm² mol⁻¹', 'label': 'A'}

1. Molar conductivity Λ_m = κ × 1000 / c, with κ in S cm⁻¹ and c in mol L⁻¹.
2. Substitute: Λ_m = (1.29 × 10⁻²) × 1000 / 0.1.
3. = 12.9 / 0.1 = 129 S cm² mol⁻¹.
4. Units check: S cm⁻¹ × cm³ / mmol → S cm² mol⁻¹.
_Source: NCERT Class 12 Chemistry, Unit 3 "Electrochemistry", §3.5_

Answer

{'text': '12.9 S cm² mol⁻¹', 'label': 'B'}

Answer

{'text': '1290 S cm² mol⁻¹', 'label': 'C'}

Answer

{'text': '1.29 S cm² mol⁻¹', 'label': 'D'}