For a Cu-Zn Daniell cell, the emf is measured to be 1.10 V under stand…

Question

For a Cu-Zn Daniell cell, the emf is measured to be 1.10 V under standard conditions. If [Cu²⁺] = 1 M and [Zn²⁺] = 0.01 M at 298 K, the cell EMF becomes

Accepted Answer

C. {'text': '+1.16 V', 'label': 'C'}

1. Cell reaction: Zn + Cu²⁺ → Zn²⁺ + Cu, n = 2.
2. E = E° − (0.059/2) log ([Zn²⁺]/[Cu²⁺]) = 1.10 − 0.0295 × log(0.01).
3. log(0.01) = −2, so the correction is −0.0295 × (−2) = +0.059.
4. E ≈ 1.10 + 0.059 ≈ +1.159 V, closest to +1.16 V.
_Source: NCERT Class 12 Chemistry, Unit 3 "Electrochemistry", §3.3_

Answer

{'text': '+0.99 V', 'label': 'A'}

Answer

{'text': '+1.10 V', 'label': 'B'}

Answer

{'text': '+1.22 V', 'label': 'D'}