The mass of copper deposited when a current of 5.0 A flows for 30 minu…

Question

The mass of copper deposited when a current of 5.0 A flows for 30 minutes through a solution of CuSO₄ (M_Cu = 63.5 g/mol, F = 96500 C) is approximately

Accepted Answer

A. {'text': '2.96 g', 'label': 'A'}

1. Charge Q = I × t = 5.0 × 30 × 60 = 9000 C.
2. Moles of electrons = 9000 / 96500 ≈ 0.0933.
3. Cu²⁺ needs 2 electrons per Cu atom, so moles of Cu = 0.0933 / 2 ≈ 0.0466.
4. Mass = 0.0466 × 63.5 ≈ 2.96 g of copper deposited.
_Source: NCERT Class 12 Chemistry, Unit 3 "Electrochemistry", §3.4_

Answer

{'text': '1.98 g', 'label': 'B'}

Answer

{'text': '5.92 g', 'label': 'C'}

Answer

{'text': '11.85 g', 'label': 'D'}