For the reaction Cu²⁺ + 2e⁻ → Cu with E° = +0.34 V, what is the cell p…

Question

For the reaction Cu²⁺ + 2e⁻ → Cu with E° = +0.34 V, what is the cell potential when [Cu²⁺] = 0.01 M at 298 K?

Accepted Answer

C. +0.281 V

1. E = E° − (0.059/n) log (1/[Cu²⁺]) = E° + (0.059/n) log [Cu²⁺].
2. n = 2. Substitute: E = 0.34 + (0.059/2) × log(0.01).
3. log(0.01) = −2. Term = (0.059/2) × (−2) = −0.059.
4. E = 0.34 − 0.059 = +0.281 V.
_Source: syllabus Chemistry, Unit 3 "Electrochemistry", §3.3_

Answer

+0.34 V

Answer

+0.399 V

Answer

+0.281 V (using log 100)

For the reaction Cu²⁺ + 2e⁻ → Cu with E° = +0.34 V, what is the cell potential when [Cu²⁺] = 0.01 M at 298 K?

Keep practising Unit 9B2: Cell EMF and Electrolytic Applications