The Nernst equation for a cell reaction at 298 K is E_cell = E°_cell − (0.059/n) log Q. Here n is
A{'text': 'The overall concentration ratio of the reactants involved', 'label': 'A'}
B{'text': 'The moles of electrons transferred per mole of reaction', 'label': 'B'}
C{'text': 'The number of ionic species produced in electrolyte', 'label': 'C'}
D{'text': 'The temperature in kelvin of the electrochemical cell', 'label': 'D'}
Answer & Solution
Correct answer: B. {'text': 'The moles of electrons transferred per mole of reaction', 'label': 'B'}
1. Nernst equation relates cell EMF to activities of species.
2. At 298 K it simplifies with the constant 0.059/n V.
3. Here n is the number of moles of electrons exchanged in the balanced cell reaction.
4. For Daniell cell (Zn → Zn²⁺ + 2e⁻ etc.), n = 2.
_Source: NCERT Class 12 Chemistry, Unit 3 "Electrochemistry", §3.3_
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