Practice free →
HomeNEET UGchemistryElectrochemistry › The Nernst equation for a cell reaction at 298 K…

The Nernst equation for a cell reaction at 298 K is E_cell = E°_cell − (0.059/n) log Q. Here n is

A{'text': 'The overall concentration ratio of the reactants involved', 'label': 'A'}
B{'text': 'The moles of electrons transferred per mole of reaction', 'label': 'B'}
C{'text': 'The number of ionic species produced in electrolyte', 'label': 'C'}
D{'text': 'The temperature in kelvin of the electrochemical cell', 'label': 'D'}
Answer & Solution
Correct answer: B. {'text': 'The moles of electrons transferred per mole of reaction', 'label': 'B'}
1. Nernst equation relates cell EMF to activities of species. 2. At 298 K it simplifies with the constant 0.059/n V. 3. Here n is the number of moles of electrons exchanged in the balanced cell reaction. 4. For Daniell cell (Zn → Zn²⁺ + 2e⁻ etc.), n = 2. _Source: NCERT Class 12 Chemistry, Unit 3 "Electrochemistry", §3.3_
Solve this in the app — NEET UG practice & 24k+ MCQs →
Related questions